COUNTRIGHT()
 Counts a particular character at the end of a string
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 Syntax

     COUNTRIGHT(<cString>,[<cCharacter|nCharacter>]) --> nNumber

 Arguments

     <cString>  Designates the character string in which the
     <cCharacter|nCharacter> character is counted.

     <cCharacter|nCharacter>  Designates the character at the end of the
     <cString> that is counted.  The default value is a space, CHR(32).

 Returns

     COUNTRIGHT() returns the number of <cCharacter|nCharacter> characters
     that appear in an uninterrupted sequence at the end of the <cString>.

 Description

     While REMRIGHT() removes trailing characters from the <cString>,
     COUNTRIGHT() only determines the number of trailing <cCharacter|
     nCharacter> characters appearing in an uninterrupted sequence at the end
     of the <cString>.

 Examples

     .  Count the blanks:

        ? COUNTRIGHT("abc   ")            // Result: 3

     .  Count the "." characters:

        ? COUNTRIGHT("abc.d..", ".")      // Result: 2

     .  In this example, there are no spaces to count:

        ? COUNTRIGHT("123456")             // Result: 0

See Also: COUNTLEFT()